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0=16.67+11.11x-x^2
We move all terms to the left:
0-(16.67+11.11x-x^2)=0
We add all the numbers together, and all the variables
-(16.67+11.11x-x^2)=0
We get rid of parentheses
x^2-11.11x-16.67=0
a = 1; b = -11.11; c = -16.67;
Δ = b2-4ac
Δ = -11.112-4·1·(-16.67)
Δ = 190.1121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.11)-\sqrt{190.1121}}{2*1}=\frac{11.11-\sqrt{190.1121}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.11)+\sqrt{190.1121}}{2*1}=\frac{11.11+\sqrt{190.1121}}{2} $
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